If y = 2(x^2+1)^3, what is dy/dx?

Since the equation for y is a composite function (applying one function to another function) we need to use the chain rule to answer this question. Firstly let u = x^2+1 . This allows us to write y = 2u^3. Differentiating y with respect to u gives us: dy/du = 6u^2. Next we differentiate our equation for u with respect to x, which gives us: du/dx = 2x Finally we use these two equations to obtain dy/dx by using the following formula: dy/dx = (dy/du)(du/dx) = (6u^2)(2x) = (6(x^2+1)^2)*(2x) = 12x(x^2+1)^2 Hence we have obtained dy/dx in terms of x and y.

Answered by Gemma C. Maths tutor

3166 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

g(x) = x/(x+3) + 3(2x+1)/(x^2 +x - 6) a)Show that g(x) =(x+1)/(x-2), x>3 b)Find the range of g c)Find the exact value of a for which g(a)=g^(-1)(a).


The curve C has the equation: 16y^3 +9x^2y-54x=0, find the x coordinates of the points on C where dy/dx = 0


Prove that n is a prime number greater than 5 then n^4 has final digit 1


How do you add or subtract complex numbers?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy