A right angled triangle with sides 7cm and 11cm, find the hypotenuse
General rule for any right angled triangle: a^2+b^2=c^2, with a and b being the shorter sides and c being the hypotenuse (the longest side). Using the equation: a=7 and b = 11 and c=hypotenuse we want to find, 7^2 +11^2=c^2, 170=c^2, hence c=square root of 170 which =13.0 (3sf)
GF
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