Edexcel C3 June 2015 Q1: tan(x)=p, where p is a constant. Using standard trigonometric identities, find the following in terms of p. a) tan(2x). b) cos(x). c) cot(x-45).

a) tan(A+B)=(tanA+tanB)/(1-tanAtanB) So, tan(2x)=[tan(x)+tan(x)]/[1-(tanx)(tanx)]. Therefore, tan(2x)=[2tan(x)]/[1-tan^2(x)] = 2p/(1-p^2). b) cos(x)=1/sec(x). Using other trigonometric identities, we know that sec^2(x)=1+tan^2(x). Hence, cos(x)=1/sqrt[1+tan^2(x)] = 1/sqrt(1+p^2). c) cot(x-45)=1/tan(x-45). tan(x-45)=[tan(x)-tan(45)]/[1+tan(x)tan(45)] tan(x-45)=[tan(x)-1]/[1+tan(x)] Therefore, cot(x-45)=[1+tan(x)]/[tan(x)-1]=(1+p)/(p-1)

LR
Answered by Liam R. Maths tutor

15938 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Integrate ln(x).


Why is the derivative of inverse tan(x) 1/(1+x^2)?


Solve the equation 3 sin^2 theta = 4 cos theta − 1 for 0 ≤ theta ≤ 360


The function f(x) is defined by f(x) = 1 + 2 sin (3x), − π/ 6 ≤ x ≤ π/ 6 . You are given that this function has an inverse, f^ −1 (x). Find f^ −1 (x) and its domain


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning