Work out the value of 125^(-2/3)

Step 1: Write 125 as an exponent. Is there any number you can multiply by itself a few times to give you 125? The answer is 5 because 5 x 5 x 5= 5 x 25 = 125. Step 2: Since we know that 125=5^3, we can replace 125 in the equation by 5^3; (5^3)^(-2/3). Step 3: Use the power rule (a^b)^c = a^(bc). Applying this rule to our equation we obtain 5^(3-2/3). Step 4: Inside the brackets we have 3*(-2/3). We can break this down further by cancelling out the 3 in the numerator with the 3 in the denominator and we will be left with -2. Step 5: Now we can simplify 5^(3*-2/3) to 5^(-2) Step 6: Apply the negative exponent rule a^(-b)= 1/(a^b)---> 5^(-2) = 1/(5^2) = 1/25

AS
Answered by Araba S. Maths tutor

8722 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise x^(2)​​​​ - 49


Solve: x^2 + y^2 = 25 y - 3x = 13


Find the equation of a line which goes through the points (1,0) and (2,5) in the form of y=mx+c


Functions f and g are such that f(x) = x^2, g(x) = x-3. Solve gf(x)=g^-1(x)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning