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What is the integral of x^x?

The integral of x^x can be solved by taking logarithms of the formula and getting xln(x) then using integration by parts it is given than u=ln(x) and dv=x therefore u'=1/x and v=(x^2)/2

using uv-(integral of)vu' to find the answer.

Answered by Nathan S. • Maths tutor

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