A curve is defined by the parametric equations x=t^2/2 +1, y=4/t -1. Find the gradient of the curve when t =2.

Firstly we would differentiate each equation with respect to t to find dx/dt and dy/dt- which gives us dx/dt=t and dy/dt=-4t^-2. Once you have found these you must divide dy/dt by dx/dt (or dy/dt x dt/dx) which is dy/dx= -4t^-3. Then you can sub t=2 into your dy/dx to find the gradient of the curve at that point to find the answer is -1/2.

AV
Answered by Asha V. Maths tutor

8149 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Express 6cos(2x)+sin(x) in terms of sin(x). Hence solve the equation 6cos(2x) + sin(x) = 0, for 0° <= x <= 360°.


Express 4sinx-cos(pi/2 - x) as a single trignometric function


Find the tangent and normal to the curve y=(4-x)(x+2) at the point (2, 8)


Integrate (x+2)/((x+5)(x-7)) using partial fractions between the limits 5 and -2, giving your answer to 3sf


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning