How do you do simple integration?

If you have an expression like 6x^2, to integrate it you have to add 1 to the power. Therefore, the new power will be 3. Then divide the whole expression by the new power so it will be 6x^3 divided by 3, which is 2x^3. The rule with simple integration is always:

  1. Add 1 to the power -
  2. Divide the whole expression by the new power
DS
Answered by Della S. Maths tutor

2856 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

The point P lies on the curve C: y=f(x) where f(x)=x^3-2x^2+6x-12 and has x coordinate 1. Find the equation of the line normal to C which passes through P.


Solve for 0=<x<360 : 2((tanx)^2) + ((secx)^2) = 1


Given that y = x^4 tan(2x), find dy/dx


The circle C has centre (3, 1) and passes through the point P(8, 3). (a) Find an equation for C. (b) Find an equation for the tangent to C at P, giving your answer in the form ax + by + c = 0 , where a, b and c are integers.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences