Integrate the following equation to find y: dy/dx = 3x^2 + 2x + 6

Notice that integration is simply the opposite of differentiation. So, if we just integrate this term-by-term then we can find an expression of y in terms of x.

So, when we integrate dy/dx becomes y.

Integrating 3x^2, we add 1 to the power and divide the coefficient by this new power. So we will get 3x^3/3 which is the same as x^3.

Then, by the same process, integrating 2x will give 2x^2/2 which is equal to x^2.

Now, if we think of 6 as the same as 6x^0 (since anything ^0 equals 1) then by the same process we get 6x^1/1 which is just 6x.

Finally, we must remember that we cannot find any term which are just a constant as they would have disappeared when y was differentiated, so we must add a +c to the end.

Bringing this all together, we get y=x^3+x^2+6x+c

MM
Answered by Murray M. Maths tutor

12039 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

There's a school in India where only 60% of students have internet access. What is the probability of choosing eight students randomly, five of whom have internet access? (Info: Each student's internet access (or lack of it) is independent from all others


Show that the integral of tan(x) is ln|sec(x)| + C where C is a constant.


How do I integrate tan^2 x?


Determine whether the line with equation 2x+ 3y + 4 = 0 is parallel to the line through the points with coordinates (9, 4) and (3, 8).


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning