Integrate the following equation to find y: dy/dx = 3x^2 + 2x + 6

Notice that integration is simply the opposite of differentiation. So, if we just integrate this term-by-term then we can find an expression of y in terms of x.

So, when we integrate dy/dx becomes y.

Integrating 3x^2, we add 1 to the power and divide the coefficient by this new power. So we will get 3x^3/3 which is the same as x^3.

Then, by the same process, integrating 2x will give 2x^2/2 which is equal to x^2.

Now, if we think of 6 as the same as 6x^0 (since anything ^0 equals 1) then by the same process we get 6x^1/1 which is just 6x.

Finally, we must remember that we cannot find any term which are just a constant as they would have disappeared when y was differentiated, so we must add a +c to the end.

Bringing this all together, we get y=x^3+x^2+6x+c

MM
Answered by Murray M. Maths tutor

12332 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the 12th term and the sum of the first 9 terms on the following Arithmetic Progression: a = 2 and d = 3


Find the tangent to the curve y = x^3 - 2x at the point (2, 4). Give your answer in the form ax + by + c = 0, where a, b and c are integers.


How do I know when to integrate using by parts or by substitution?


What is De Moivre's theorem?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning