Find the integral of xcosx(dx)

Firstly, let's split the equation "xcosx" into two parts to integrate them separately. 1) Let u=x and dv/dx=cosx 2)As the integral of x is 1, du/dx=1 3)To find v, we integrate cosx to get v=sinx Using the formula: The integral of x.dv/dx=uv-integral of v.du/dx So, to reiterate we have: u=x du/dx=1 v=cosx dv/dx=sinx So, using the formula, we need to find uv and the integral of v.du/dx 1) uv=x.sinx=xsinx 2) v.du/dx=sinx.1=sinx By using the formula as listed above: 1) xsinx-integral(sinx)= xsinx-(-cosx)+c= xsinx+cosx+c Therefore, the answer is xsinx+cosx+c

AF
Answered by Amelia F. Maths tutor

16366 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Tom drink drives two days a week, the chance of him being caught per day is 1 in 100. What is the chance he will not be driving after a) one week? b) one year?


Locate the position and the nature of any turning points in the function: 2x^3 - 9x^2 +12x


The equation f(x) =x^3 + 3x is drawn on a graph between x = 0 and x = 2. The graph is then rotated around the x axis by 2π to form a solid. What is the volume of this solid?


By forming and solving a quadratic equation, solve the equation 5*cosec(x) + cosec^2(x) = 2 - cot^2(x) in the interval 0<x<2*pi, giving the values of x in radians to three significant figures.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences