Solve the simultaneous equations: y=3x+2, x^2+y^2=20

y=3x+2 x^2+y^2=20 x^2+(3x+2)^2=20 x^2+(3x+2)(3x+2)=20 x^2+(9x^2+6x+6x+4)=20 x^2+(9x^2+12x+4)=20 10x^2+12x+4=20 10x^2+12x-16=0 5x^2+6x-8=0 (5x-4)(x+2)=0 5x-4=0, x+2=0 x=4/5=0.8, x=-2 y=3x+2, y=3x+2 y=3(0.8)+2, y=3(-2)+2 y=4.4, y=-4 When x=0.8, y = 4.4 When x=-2, y=-4

DC
Answered by Daniela C. Maths tutor

15102 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do I solve simultaneous equations?


Bhavin, Max and Imran share 6000 rupees in the ratios 2 : 3 : 7 Imran then gives 3/5 of his share of the money to Bhavin. What percentage of the 6000 rupees does Bhavin now have? Give your answer correct to the nearest whole number.


How to differentiate 9x^2+ 4x-7=0


Represent x = 0.0154 recurring as a fraction.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning