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4^(n)-1 factors to (2^(n)-1)(2^(n)+1) by difference of two squares by definition of a prime (only has factors 1 and itself (given that itself isn't 1))So Exactly one of the brackets should = 1 for 4^(n)-1...

for x in range(1,8) : print(x) The range(1,8) function gives us an array of numbers from 1 to 7. The number on the right is the upper bound of the numbers which is why only 1 to 7 is returned.From here, a...