Top answers

All subjects
All levels

How do you know if the second derivative of an equation is a maximum or a minimum?

If the second derivative of an equation is positive (d2y /dx2 > 0), we can see that this point on a curve is a minimum. This is because, where the first derivative finds the grad...

JG
Answered by Jessica G. Maths tutor
2969 Views

Use integration by parts to find the integral of ln x by taking ln x as the multiple of 1 and ln x

For integration by parts, the integral is uv - ∫ u' v dx. First we take u = ln x and v' = 1. While we could have u and v' be the opposite at this stage, it becomes apparent later on that we can't do this ...

JC
Answered by Jack C. Maths tutor
4444 Views

Which of these statements is correct? 1. The kidneys filter the blood and remove waste products from the body. 2. The kidneys are involved in digesting food. 3. In a healthy individual, the Kidneys produce urine that contains high levels of glucose.

Only statement one is true as the kidneys are not involved in digestion, but do filter the blood of waste products. Glucose is found in high concentrations in the urine of diabetics, who cannot absorb glu...


a) How can an element be classified as a transition metal, considering only electronic arrangement? (1 mark) b) In terms of electrons, why is aqueous copper(II) sulphate solution red? (3 marks) c) EDTA is a bidentate ligand. What is a bidentate ligand?(2)

a) Partially filled/incomplete d shell.
b) Light is absorbed by an electron, exciting it and is promoted to a higher energy d orbital. The colour seen is the complimentary colour of that absorbed (in...

JO
Answered by James O. Chemistry tutor
1909 Views

25cm^3 of 0.1M NaOH is reacted with 0.01M HCl until the equivalence point is reached. What volume of HCl was required to be added?

0.025 dm^3 x 0.1 mol dm^-3 = 0.0025 molsince mols must be equal:mols of HCl = 0.0025/0.01 =250cm^3To get to the answer I would first check the student was first able to identify the key words and numbers ...

GW
2420 Views

We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences