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In order to work out the equation for a line, you need the gradient of the line and the coordinates of a point on the line. To find the gradient on the line, you look at two points on the line and calcula...
If it's not sticking in your head; don't. I find it's easier to just remember what the point of a Taylor expansion is: to express a function as an infinite polynomial, often because polynomials are ea...
If you have a claim which says something about every element in a list of elements with each element depending on previous elements, induction might be a useful starting point. In your exams, that "l...
We can start by recognising one of our properties of log. That is loga(x) - loga(y) = loga(x/y). Performing this on our question we get: log3((3b+1)/(a-2)) = -1...
To start, let us recall the form of a quadratic equation. y = ax2 + bx + c. When making x the subject of the formula and setting y = 0, we get the quadratic formula, as you may have seen before...
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