Top answers

All subjects
A Level

Find the derivative of f(x)=exp((tanx)^(1/2))

We use the chain rule. Let u(x)=exp(x), v(x)=x1/2, w(x) = tan(x).
Then f(x) = u(v(w(x))). So by the chain rule, f'(x) = u'(v(w(x)))*(v(w(x)))'.
u'(x) = exp(x).
By the chain rule...

LD
Answered by Luke D. Maths tutor
4135 Views

How are proteins synthesised?

Proteins are coded for by genes (a sequence of DNA that codes for a specific polypeptide), in the nucleus the DNA is unwound by an enzyme and then another enzyme with copy the template strand to make a mo...

BR
Answered by Billy R. Biology tutor
2926 Views

The price of coffee beans rose from $1.15 to $1.40 between June and August 2017. A possible cause of this rise is: a) Improved weather conditions in coffee-growing countries; b) An increase in national minimum wage in coffee growing countries.

The correct answer is b).The price mechanism is defined as the interaction between supply and demand for a good, which determines price such that quantities supplied and demanded are equal.An increase in ...

GS
2237 Views

Acid HA has a Ka of 2.00 x 10-4mol dm-3. A solution was made by adding 15cm3 of 0.34 M NaOH to 25cm3 of 0.45M HA. Calculate the moles and the concentration of A- and HA in this solution. Using the expression for Ka calculate the pH of the solution

Write the equation: NaOH + HA --> NaA + H2O. Find the moles of A-: the moles of A-= the moles of NaO...

HS
Answered by Hibba S. Chemistry tutor
6994 Views

How would you calculate the vertical and horizontal components of the velocity of an object with an initial velocity of 15m/s which is travelling upwards at an angle of 30 degrees to the horizontal?

With these sort of questions involving components, I would always advise drawing a diagram of the problem so that you're clear of the situation!In this case we have an object that is travelling at a speed...

JP
Answered by Joseph P. Physics tutor
6678 Views

We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning