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A curve has equation (x+y)^2=x*y^2, find the gradient of the curve at a point where x=1

  1. Differentiating left hand side: 2(x+y)(1+dy/dx) from the chain rule 2. Differentiating right hand side: y2+2xy(dy/dx) from the product rule 3. Equating sides and taking out factors of dy/...
PK
Answered by Peter K. Maths tutor
4471 Views

Find the equation of a straight line that passes through the coordinates (12,-10) and (5,4). Leaving your answer in the form y = mx + c

Finding the gradient (m): The gradient is the change in y-axis over the change in x-axis Δy = -10-4= -14        Δx = 12-5=7 Δy/Δx = -14/7 = -2 Ac...

MM
Answered by Martin M. Maths tutor
8981 Views

Find the vector equation of the line of intersection of the planes 2x+y-z=4 and 3x+5y+2z=13.

The line of intersection will be parallel to both planes. We can write the equations of the two planes in 'normal form' as r.(2,1,-1)=4 and r.(3,5,2)=13 respectively. We can then read off the normal vecto...

RS
20230 Views

In terms of particles, explain how resistance arises in metal conductors and why does this resistance increases with temperature.

Resistance is due to the collision of free electrons with the metal ions of the conductor. When the temperture increases, the metal ions have more energy and vibrate. This increases the frequency of colli...

RR
Answered by Rhys R. Physics tutor
13371 Views

The polynomial f(x) is define by f(x) = 3x^3 + 2x^2 - 8x + 4. Evaluate f(2).

f(x) = 3x^3 + 2x^2 - 8x + 4

f(2) = 3(2)^3 + 2(2)^2 - 8(2) + 4

f(2) = 3(8) + 2(4) - 8(2) + 4

f(2) = 24 + 8 - 16 +4

f(2) = 20

SW
Answered by Sophie W. Maths tutor
4140 Views

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