Find the equation of a straight line that passes through the coordinates (12,-10) and (5,4). Leaving your answer in the form y = mx + c

Finding the gradient (m): The gradient is the change in y-axis over the change in x-axis Δy = -10-4= -14        Δx = 12-5=7 Δy/Δx = -14/7 = -2 Accumilating the equation: The equation of a straight line can be deduced by a simple formula y- ya = m(x- xa)      where a is a coordinate which lies on the lie.

The equation: y - 4 = -2(x - 5) y - 4 = -2x + 10

Therefore the equation of the line: y= -2x+14

Answered by Martin M. Maths tutor

7623 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Curves C1 and C2 have equations y= ln(4x-7)+18 and y= a(x^2 +b)^1/2 respectively, where a and b are positive constants. The point P lies on both curves and has x-coordinate 2. It is given that the gradient of C1 at P is equal to the gradient of C2 at P.


I don't understand how to visualise differentiation, please could you show my an example to allow me to understand what it actually is better?


How do we work out the asymptotes of the graph y=1/x -5


The curve y = 4x^2 + a/ x + 5 has a stationary point. Find the value of the positive constant a given that y-ordinate of the stationary point is 32.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy