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Curves C1 and C2 have equations y= ln(4x-7)+18 and y= a(x^2 +b)^1/2 respectively, where a and b are positive constants. The point P lies on both curves and has x-coordinate 2. It is given that the gradient of C1 at P is equal to the gradient of C2 at P.

y= ln(4x-7)+18 y= a(x^2 +b)^1/2
At x=2 dy/dx = dy/dx and y =y
At x =2 y = ln(8-7) +18 y = ln 1 +18 y =18
At x = 2 18=a(4 +b)^1/2 18/(4+b)^1/2= a
y=ln(4x-7)+18dy/dx= 4/(4x...

JM
Answered by Jordan M. Maths tutor
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Calculate the value of the definite integral (x^3 + 3x + 2) with limits x=2 and x=1

a) Integrate the given expression using integration laws we have learnt to give [(x^4)/4 + (3(x^2))/2 + 2x ] and you do not need a +c constant as we have limits.b) Substitute the limits into the equation ...

Answered by Maths tutor
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Solve the inequality 6x - 7 + x^2 > 0

Firstly rearrange the quadratic such that the coefficient of x2 is positive (already done in this example) and the quadratic is in the form of ax2 +bx + c, then solve for ...

Answered by Maths tutor
3500 Views

Potassium Chlorate(VII) decomposes to produce Potassium Chloride and Oxygen. Using the following data calculate the enthalpy change of this decomposition: Enthalpy of formation(KClO4) = -430 kJ mol-1, Enthalpy of formation(KCl) = -440 kJ mol-1

Firstly the equation of this decomposition should be worked out to be the following
KClO4(s) --> KCl(s) + 2O2(g)
The enthalpy of formation has been given for both KClO<...

Answered by Chemistry tutor
17654 Views

Let N be an integer not divisible by 3. Prove N^2 = 3a + 1, where a is an integer

For N to be not divisible by 3, N can either be of the form 3k + 1 (1,4...) or 3k + 2 (2,5...), where k is an integer.
The proof can then be done by checking both 3k + 1 and 3k + 2 when N is squared...

Answered by Maths tutor
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