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The key is to look at the first and second derivatives of that function. Remember that a turning point always has the first derivative equal to zero. Then, the sign of the second derivative indicates if t...
Starting with x=2cosu, rearrange for u to get u=arccos(x/2), then find the upper and lower limits of the integral. We find that our lower limit goes from 1 to pi/3, ad our upper limit goes from root 2 to ...
1/2 *e^(x)(sin x -cos x)
y=5x2-2x+3 Differentiate to find the equation of the gradient of the curvedy/dx=10x-2 Substitute x=0 to find the gradient at the point x=0dy/dx=-2y=50^2-2Answered by • Maths tutor5496 Views
In order to answer this question, the expression on the left side of the equation needs to be factorised. This can be done in three stages. 1) finding a factor by subbing in common integers (0, +/- 1, +/-...
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