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Maths
A Level

intergrate xcos(2x) with respect to x

The function of x has two separate x terms multiplied by each other. Therefore, the appropriate way to integrate this function is by parts. The equation for integration by parts is [integral (u.dv/dx)] = ...

MI
Answered by Mark I. Maths tutor
5411 Views

Having a rectangular parking lot with an area of 5,000 square yards that is to be fenced off on the three sides not adjacent to the highway, what is the least amount of fencing that will be needed to complete the job?

We can turn this into a constrained optimization problem. Let's denote x the side of the parking lot that is perpendicular to the highway, and y the side that is parallel to the highway. We therefore need...

EB
Answered by Emil B. Maths tutor
5678 Views

find the integral of (2x - (3x^1/2) +1) between 9 and 4

2x become x2

3x1/2 becomes 2x3/2

1 becomes x

sub 9 into values for x = (81 - 54 +9) which equals 36

sub 4 into values for x = (16 - 16 + 4) whi...

AH
Answered by Amber H. Maths tutor
2945 Views

Express 9^(3x + 1) in the form 3^y , giving y in the form ax + b, where a and b are constants.

9^ (3x + 1)

We know that 3 to power of 2 equals 9.  3x3 = 3^2 = 9, 

= 3^ (2 * [3x + 1])

We simply the term because 2 * [3x + 1] = 6x + 2

= 3^ ( 6x + 2) 

This term is in ...

WL
Answered by William L. Maths tutor
4207 Views

A tunnel has height, h, (in metres) given by h=14-x^2 where x is the horizontal distance from the centre of the tunnel. Find the cross sectional area of the tunnel. Also find the maximum height of a truck passing through the tunnel that is 4m wide.

Firstly, solve 0=14-x^2 to find the horisontal distance to the edges of the tunnel. x1=sqrt(14), x2= -sqrt(14).

Integrate h=14-x^2 between x1 and x2 28*sqrt(14) -(2(sqrt(14)^3))/3. This is the requ...

JG
Answered by James G. Maths tutor
7384 Views

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