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Maths
A Level

Find the integral of tan^2x dx

You can not integrate tan2x but you can integrate sec2x Since sec2x = 1 + tan2x  Then tan2

NP
Answered by Nandini P. Maths tutor
19981 Views

How do i solve two linear simultaneous equations 2x+y=7 & 3x-y=8 ?

To start with, try and spot whether or not two of the coeffecients (numbers next to the letters) are the same for either question (i.e. could be a 3x in one equation and a 3x in the other). This also work...

TB
Answered by Tom B. Maths tutor
3753 Views

Find the equation of the tangent to the unit circle when x=sqrt(3)/2 (in the first quadrant)

Unit circle: x2 + y2 = 1 when x = sqrt(3)/2:  y2 = 1 - (sqrt(3)/2)2  y2 = 1 - 3/4  y2 = 1/4  y = 1/2 or -1/2 (first quadrant, so y is posi...

KJ
Answered by Kiran J. Maths tutor
3678 Views

Integral of (2(x^3)-7)/((x^4)-14x)

Set f(x)= (x^4)-14x. f’(x)=4(x^3)-14=2(2(x^3)-7). Thus we can write (2(x^3)-7)/((x^4)-14x)=(1/2)f’(x)/f(x). The integral of f’(x)/f(x)=ln|f(x)|+c. Thus the integral of (2(x^3)-7)/((x^4)-14x) is (1/2)(ln|f...

IK
Answered by Issy K. Maths tutor
2923 Views

A curve has parametric equations: x = 3t +8, y = t^3 - 5t^2 + 7t. Find the co-ordinates of the stationary points.

First differentiate: dx/dt = 3,   dy/dt = 3t2 - 10t + 7

Using the chain rule: dy/dx = dy/dt * dt/dx = (3t2 - 10t + 7)/3 

At stationary points, the...

RB
Answered by Robbie B. Maths tutor
5130 Views

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