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To get the required tangent equation we need its gradient and the coordinates of a point it passes through. We can then substitute it into the formula y - y1 = m(x - x1). 1. ...
You use integration by parts if there's more than one function of x. For example; to integrate xsin(x) you'd use integration by parts as this is two functions of x. The formula to remember is I(udv) =...
Using integration by parts, by substituting ln(3x) as u and x^8 as dv/dx, use the formula to plug in the values and complete the calculation to get (x^9)(ln(3x)-1/9)/9
We can see that we have the product of two different functions, and so we need to use the product rule. We will separate the function and label each part u and v for clarity. So we let u = 2ex ...
First, we must rearrange to give 2tan(θ) = 5x. Differentiate both sides with respect to x: 2sec2(θ)dθ/dx = 5 Use identity sin2(θ) + cos2(θ) = 1, dividing through by cosCWAnswered by Callum W. • Maths tutor3877 Views
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