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You would use the product rule. uv'=uv- u'vdx. In this case we would allocate u= ln x and v'=1 so u'=1/x and v=x so uv=xlnx whilst u'v=x/x=1 so we would have xln(x) -1dx. Next we would get xln(x)-x +c
Option 1 - Differentiate using product rule giving dy/dx = cos2(x) - sin2(x). (2 marks) Subbing in x as pi (1 mark) then gives (-1)2 + (0)2 . ...
let us start by taking two points on the curve y=x2, the first with x-coordinate x, and the second x+Δx and drawing a straight line between them. We can form a right-angled triangle, with two s...
Differentiating a function, f(x,t) with respect to a varible, such as x or t, tells you rate of change of the fucntion with respect to that varible. By subbing in a value for x into you differentiated fu...
3cos^2(theta) - 3sin^2(theta) - 5cos(theta) + 2 = 0
3cos^2(theta) + 3cos^2(theta) - 3 - 5cos(theta) + 2 = 0
6cos^2(theta) - 5cos(theta) - 1 = 0
delta = 25 + 24 = 49
cos(theta) ...
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