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*The usual mistake with inequalities is not with a students algebra, but with lack of consideration of the inequality signs. During a tutorial I would show their false method and my correct one and also s...
Use the product rule:
d/dx(fg) = f'g + fg'
f = x2 f' = 2x g = sin(x) g' = cos(x)
answer = 2xsin(x) + x2cos(x)
As the tangent has the same gradient as the curve at the particular point, we need to find the gradient of the curve. To find the gradient we need to differentiate. Due to there being two variables in thi...
Firstly, note that a stationary point can either be a local maximum, local minimum or point of inflexion. Now suppose you have a differentiable function (a graph which has a unique gradient/derivative at ...
How might one simplify this? It looks as though raising both sides to the power 4 is the way to go, but it is not immediately obvious how to do this. In order to get both sides into the form 'log of somet...
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