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Maths
A Level

Given that y = (( 4x + 1 )^3)sin(2x), find dy/dx.

This is an example of the chain rule.

The chain rule is the following: if y = uv, then dy/dx = udv/dx + vdu/dx

So in this case, u = ( 4x + 1)^3, v = sin(2x)

du/dx = (3)(4)( 4x + 1 )^2...

DS
Answered by Danielle S. Maths tutor
4971 Views

Find ∫ x^2(ln(4x))dx

 ∫xln(4x)dx

Firstly , identify this question as integration by parts. Therefore set one half as value 'u' and one as value 'dv'.

Here we will set u = ln(4x).

Therefore: d...

SF
Answered by Sally F. Maths tutor
10728 Views

When trying to solve inequalities (e.g. 1/(x+2)>x/(x-3)) I keep getting the wrong solutions even though my algebra is correct.

*The usual mistake with inequalities is not with a students algebra, but with lack of consideration of the inequality signs. During a tutorial I would show their false method and my correct one and also s...

TH
Answered by Timothy H. Maths tutor
3673 Views

Find the value of: d/dx(x^2*sin(x))

Use the product rule:

d/dx(fg) = f'g + fg'

f = x2    f' = 2x   g = sin(x)  g' = cos(x)

answer = 2xsin(x) + x2cos(x)

WR
Answered by Will R. Maths tutor
9420 Views

Find the equation for the tangent to the curve y^3 + x^3 + 3x^2 + 2y + 8 = 0 at the point (2,1)

As the tangent has the same gradient as the curve at the particular point, we need to find the gradient of the curve. To find the gradient we need to differentiate. Due to there being two variables in thi...

AE
Answered by Aphishek E. Maths tutor
3905 Views

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