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Firstly, implicitly differentiate the function to find dy/dx in terms of y and x: dy=dx = (-x-2y)/(2x+y). Secondly, set this equal to zero to obtain an expression of y in relation to x or vice versa: x=-2...

The general quadratic equation is ax^2+bx+c=0, now we need to Complete The Square, which allows us to have only one "x" term. First, divide the equation by "a", leaving us with x^2... ...

Before you start it is best to gather as much information as you can about the function. The most important things to find are any roots - as these will tell where the graph should cross the axis - and th...

Here we have an equation involving absolute values. As a general rule |a| = +a and |a| = -a. We can apply that to our RHS. In the first case we get that 3x + 4 = 3x - 11, however after we subtract 3x from...

Here z is a complex number, and therefore, z = a + bi. Thus, our equation becomes (a + bi)^2 = i. Expanding the brackets we get a^2 + 2abi + (b^2)(i^2) = i. Since i is the squ...