Top answers

Maths
A Level

Outline the various ways that you can differentiate a function

The ways to differentiate a function depend on the function itself. If there is only one x value in the function you can differentiate as normal (hard to explain on a computer), yet if the function contai...

BN
Answered by Barnaby N. Maths tutor
4283 Views

Find f''(x), Given that f(x)=5x^3 - 6x^(4/3) + 2x - 3

In order to get from f(x) to f''(x) we need to differentiate the function f(x) with respect to x and then differentiate the resulting function with respect to x again. When differentiating f(x), split the...

AB
Answered by Alexey B. Maths tutor
7582 Views

A particle A rests on a smooth inclined plane, it is connected to a particle B by a light inextensible string that is passed over a fixed smooth pulley at the top of the plane. B hangs freely. Find the acceleration of the system and tension in the string.

Full Question: A particle A of mass 2.5kg is at rest on a smooth inclined plane at an angle of 25 degrees, it is connected to a particle B of mass 1.5kg by a light inextensible string which lies along a l...

KW
Answered by Kyle W. Maths tutor
10459 Views

Edexcel C3 June 2015 Q1: tan(x)=p, where p is a constant. Using standard trigonometric identities, find the following in terms of p. a) tan(2x). b) cos(x). c) cot(x-45).

a) tan(A+B)=(tanA+tanB)/(1-tanAtanB) So, tan(2x)=[tan(x)+tan(x)]/[1-(tanx)(tanx)]. Therefore, tan(2x)=[2tan(x)]/[1-tan^2(x)] = 2p/(1-p^2). b) cos(x)=1/sec(x). Using other trigonometric identities, we know...

LR
Answered by Liam R. Maths tutor
15440 Views

When do I use the chain rule and when do I use the product rule in differentiation?

These are two really useful rules for differentiating functions. We use the chain rule when differentiating a 'function of a function', like f(g(x)) in general. We use the product rule when differentiatin...

MO
Answered by Michael O. Maths tutor
152911 Views

We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences