Top answers

How do you find a turning point of a function using differentiation?

To find the location of turning points on a function, find the first derivative of the function, and then set the result to 0. if you then solve this equation, you will find the locations of the turning poin...
NS
Answered by Nathan S. • Maths tutor
60407 Views

A particle A of mass 0.1kg is moving at a speed of 1.5m/s to the right. It collides with a particle B of mass 0.3kg moving at a speed of 1.1m/s to the right. Calculate change in momentum of particle A if particle B has a speed of 1.4m/s after collision.

Momentum is conserved during the collision.Momentum = mass x velocityMomentum before = momentum after(mv) P1 + (mv) Q1 = (mv) P2 + (mv) Q2 (0.1 x 1.5) + (0.3 x 1.1) = 0.1v P2 + (0.3 x 1.4)v P2 = 0.6m/sChange...
JS
Answered by Juliet S. • Maths tutor
4016 Views

What is the area under the graph of (x^2)*sin(x) between 0 and pi

To solve this integral you need to use integration by parts twice. You separate the two term in the integral into x^2 and sin(x). You then multiple x^2 by the integral of sin(x) (-cos(x)) and apply the upper...
KP
Answered by Khalil P. • Maths tutor
4948 Views

A curve has parametric equations x = 1- cos(t), y = sin(t)sin(2t). Find dy/dx.

Here we have x(t) and y(t) which are both functions of t, but we want dy/dx, which doesn't involve t, we therefore need to use the chain rule. The chain rule tells us that: dy/dx = (dy/dt) x (dt/dx).y = sin(...
WM
Answered by William M. • Maths tutor
7476 Views

A curve is defined by the equation y^2 - xy + 3x^2 - 5 = 0. Find dy/dx.

2y dy/dx - x dy/dx - y + 6x = 0dy/dx (2y-x)= y-6xdy/dx= (y-6x)/(2y-x)
WA
Answered by Witold A. • Maths tutor
5523 Views