A curve is defined by the equation y^2 - xy + 3x^2 - 5 = 0. Find dy/dx.

2y dy/dx - x dy/dx - y + 6x = 0dy/dx (2y-x)= y-6xdy/dx= (y-6x)/(2y-x)

WA
Answered by Witold A. Maths tutor

4900 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Differentiate y = (3x − 2)^4


The curve C has the parametric equations x=4t+3 and y+ 4t +8 +5/(2t). Find the value of dy/dx at the point on curve C where t=2.


How do we work out the asymptotes of the graph y=1/x -5


How do you differentiate a function?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences