A curve is defined by the equation y^2 - xy + 3x^2 - 5 = 0. Find dy/dx.

2y dy/dx - x dy/dx - y + 6x = 0dy/dx (2y-x)= y-6xdy/dx= (y-6x)/(2y-x)

WA
Answered by Witold A. Maths tutor

5218 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Find the exact solution of the following equation: e^(4x-3) = 11


The curve C has equation (4x^2-y^3+3^2x)=0. The point P (0,1) lies on C: what is the value of dy/dx at P?


Using trigonometric identities, show that (cos(x) + sin(x))^2=1+sin(2x)


Integrate x*ln(x) with respect to x


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning