A curve is defined by the equation y^2 - xy + 3x^2 - 5 = 0. Find dy/dx.

2y dy/dx - x dy/dx - y + 6x = 0dy/dx (2y-x)= y-6xdy/dx= (y-6x)/(2y-x)

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Answered by Witold A. Maths tutor

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