Answers
>
Maths
>
A Level
>
Article
A curve is defined by the equation y^2 - xy + 3x^2 - 5 = 0. Find dy/dx.
2y dy/dx - x dy/dx - y + 6x = 0dy/dx (2y-x)= y-6xdy/dx= (y-6x)/(2y-x)
WA
Answered by
Witold A.
•
Maths tutor
5542 Views
See similar Maths A Level tutors
Related Maths A Level answers
All answers ▸
Find the area under the curve of y=x^2 between the values of x as 1 and 3
Find dy/dx when y = 5x^6 + 4x*sin(x^2)
If y=3x^3e^x; find dy/dx?
Given y=rootx + 4/rootx = 4, find the value of dy/dx when x=8, writing your answer in the form aroot2, where a is a rational number.