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Find the equation of the tangent to the circle x^2 + y^2 + 10x + 2y + 13 = 0 at the point (-3, 2)

First, what is a tangent? A line which touches a circle (or ellipse) at just one point. In our case (-3,2) As it touches the line at one point, it is perpendicular the radius at (-3,2). Which implies that th...
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Answered by Patrick D. Maths tutor
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The line L has equation y=5-2x. Find an equation of the line perpendicular to L, which passes through the point P (3,-1).

The gradient of the line L is -2 so the gradient of the line perpendicular to L will be the negative reciprocal of -2 which is 1/2.The equation of the line perpendicular to L will be y=mx+c where m is the gr...
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Answered by Katie N. Maths tutor
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What is product rule differentiation?

Product rule differentiation, is a form of differentiation which is used to calculate the derivative, i.e. the gradient of the function, of a function f(x) which is made up of one function g(x) multiplied by...
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Answered by Thomas F. Maths tutor
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What are differences between speed and velocity, velocity and speed and acceleration?

Firstly, it is important to know the difference between scalars and vectors. Scalars are just a number associated with a measured quantity, while vectors are a number AND a direction associated with a quanti...
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Answered by Felix P. Maths tutor
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The curve C has equation 4x^2 – y^3 – 4xy + 2^y = 0 The point P with coordinates (–2, 4) lies on C . Find the exact value of dy/dx at the point P .

Since we need to find dy/dx, we must first differentiate the equation implicitly which gives us: 8x - 3y 2 dy/dx - 4y - 4xdy/dx + 2 y ln(2)dy/dx = 0. Because we are given a point, we can substitute in the x ...
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Answered by Samuel N. Maths tutor
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