The curve C has equation 4x^2 – y^3 – 4xy + 2^y = 0 The point P with coordinates (–2, 4) lies on C . Find the exact value of dy/dx at the point P .

Since we need to find dy/dx, we must first differentiate the equation implicitly which gives us: 8x - 3y2dy/dx - 4y - 4xdy/dx + 2yln(2)dy/dx = 0. Because we are given a point, we can substitute in the x and y values of that point which results in: -16 - 48dy/dx - 16 + 8dy/dx + 16ln(2)dy/dx = 0.We now have an equation which is easily solved by rearrangement. First we bring all dy/dx's to one side: 16ln(2)dy/dx - 40dy/dx = 32. And then we isolate dy/dx: dy/dx(16ln(2) - 40) = 32 => dy/dx = 32/(16ln(2) - 40).

SN
Answered by Samuel N. Maths tutor

8466 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Given that sin(x)^2 + cos(x)^2 = 1, show that sec(x)^2 - tan(x)^2 = 1 (2 marks). Hence solve for x: tan(x)^2 + cos(x) = 1, x ≠ (2n + 1)π and -2π < x =< 2π(3 marks)


How do you differentiate (2x+xe^6x)/(9x-(2x^2)-ln(x)) w.r.t. x?


How to integrate by parts


Given y = 3x^(1/2) - 6x + 4, x > 0. 1) Find the integral of y with respect to x, simplifying each term. 2) Differentiate the equation for y with respect to x.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning