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Find the minimum value of the function, f(x) = x*exp(x)

The minimum value lies where the tangent to the curve has a gradient of zero and the curve approaching from both directions increases in value. This is done by finding the first and second derivatives of the...
RT
Answered by Robin T. Maths tutor
4077 Views

Differentiate y=e^(x)*sin(x) with respect to x

y=e^(x)*sin(x) Use the product rule: y'=uv'+vu' y=u*v Differentiate: u=e^(x) u'=e^(x) v=sin(x) v'=cos(x) Sub into the product rule: y'=e^(x)*cos(x)+e^(x)*sin(x) Take out a factor of e^(x): y'=e^(x)*(cos(x)+s...
AJ
Answered by Alexander J. Maths tutor
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Find dy/dx in terms of t of the parametric equations x=4e^-2t, y=4 - 2e^2t

x=4e -2t , y=4-2e 2t dy/dx = dy/dt * dt/dx dy/dt = -4e 2t dx/dt = -8e -2t dt/dx = -1/8 * e 2t dy/dx = (-4e 2t )(-1/8 * e 2t ) = 1/2 * e 4t dy/dx = 0.5e 4t
JM
Answered by Josh M. Maths tutor
6086 Views

Core 1 question: Draw the graph "y = 12 - x - x^2"

I always found drawing graphs one of the hardest parts of maths - especially in C1 where you cannot use a calculator to help you. So, I used some simple rules to find key parts of the graph which would simpl...
TH
Answered by Tess H. Maths tutor
8542 Views

Solve x^2 > |5x - 6|

We need to split the problem into two cases to remove the abs sign. Case 1: 5x - 6 >= 0, equivalent to x >= 6/5. In this case the problem is now to find the values of x that satisfy x 2 > 5x - 6. Re...
JH
Answered by James H. Maths tutor
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