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Maths
A Level

Solve the equation 3sin^2(x) + sin(x) + 8 = 9cos^2(x), -180<X<180. Then find smallest positive solution of 3sin^2(2O-30) + sin(2O-30) + 8 = 9cos^2(2O-30).

Cos^2(x) + sin^2(x) = 1. Therefore Cos^2(x) = 1 - sin^2(x). So equation becomes 3Sin^2(x) + sin(x) + 8 = 9(1 - sin^2(x)). Then becomes 12sin^2(x) + sin(x) - 1This is quadratic equation, solved to (4sin(x)...

JR
Answered by Joshua R. Maths tutor
13338 Views

differentiate 3x^56

=(3x56)x55

MG
Answered by Madalina G. Maths tutor
3458 Views

The curve with the equation: y=x^2 - 32sqrt(x) + 20 has a stationary point P. Find the coordinates of P.

A stationary point implies that the gradient at this point will be equal to 0, it is a turning point in the graph. So we need to find the value of X at which dy/dx = 0. [where dy/dx is the gradient.]So we...

MB
Answered by Maninder B. Maths tutor
9101 Views

Solve the equation 2(cos x)^ 2=2-sin x for 0 <=x<=180

Recall the identity ((cos x)^2+(sin x)^ 2=1). Rearrange the identity to give cos x in terms of sin x. Substitute this into the equation. Rearrange so all terms are on one side of the equation and factorie...

PG
Answered by Pablo G. Maths tutor
3571 Views

If I had an equation with both 'x' and 'y' present, how would I find the gradient?

Using the equation (x+y)2=xy2 as an example base to see how it would work in practice. The most important fact is that dy/dx =y'. Simply put, the derivative of y is ...

OK
Answered by Oli K. Maths tutor
2870 Views

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