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Maths
A Level

How do you find the x co-ordinates of the stationary points of a curve with the equation y = 10x - 2x^2 - 2x^3

First to find the stationary points, you have to differentiate the equation of the curve y, to give you (dy/dx) = 10 - 4x - 6x^2After differentiating the equations, the points at which the curve is statio...

DM
Answered by David M. Maths tutor
3418 Views

Integrate 2x^5 + 7x^3 - (3/x^2)

Integrating xn gives you xn+1/(n+1).Integral of 2x5 is 2x6/6 = x6/3. The integral of 7x3 is 7x4/4.-(3/x2) can be rew...

AP
Answered by Alexander P. Maths tutor
4309 Views

Differentiate y = 5x^3 + 7x + 3 with respect to x

When differentiating with respect to x, we multiply the coefficient of the 'x' by the power of the 'x', and subtract one from the power of 'x'. For example:y = 5x^5dy/dx = (55)x^(5-1) = 25x^4If the po...

JK
Answered by Jordan K. Maths tutor
4071 Views

(Core 2) Show that the region bounded by the curve y = 7x+ 6 - (1/x^2), the x axis and the lines x = 1 and x = 2 equals 16

The question wants us to confirm the answer so the marks will be in the method unlike most questions which require you to find the answer. How to approach this is by thinking what ways can we calculate ar...

LJ
Answered by Lewis J. Maths tutor
4191 Views

A curve (C) with equation y=3x^(0.5)-x^(1.5) cuts the X axis at point A and the origin, calculate the co-ordinates of point A.

Insert 0 into the equation in place of Y as the Y co-ordinate is always 0 across the X-Axis.0 = 3x^0.5-x^1.5The x^0.5 can be factored out from the 3x^0.5 and the x^1.5 giving you...x^0.5(3-x^1) = 0 [As x^...

JM
Answered by Jack M. Maths tutor
3500 Views

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