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Maths
A Level

A curve is defined by the parametric equations x = 2t and y = 4t^2 + t. Find the gradient of the curve when t = 4

the gradient of the curve = dy/dx
and dy/dx = (dy/dt)(dt/dx)
dy/dt = 8t + 1
dx/dt = 2 therefore dt/dx = 1/2
dy/dx as above = (8t + 1) * 1/2 = (8t + 1)/2
where t = 4, dy/dx = (8*4...

AB
Answered by Angus B. Maths tutor
5029 Views

a) i) find dy/dx of y = 3x^4 - 8x^3 - 3 ii) then find d^2y/dx^2 b) verify that x=2 at a stationary point on the curve c c) is this point a minima or a maxima

So the first step is to find the first differential of yTo do this we simply have to differentiate:so with C being our coefficient, n being the power that x is.we need to reduce the power of x by 1, whils...

CM
Answered by Charlie M. Maths tutor
3037 Views

When you are working out dy/dx = 0, why do you do this and what does it mean?

It relates back to what we actually mean why we say dy/dx. Simply put, dy/dx means the rate of change of y with respect to the rate of change in x over a infinitely small space of time. Therefore, when we...

MJ
Answered by Matthew J. Maths tutor
23290 Views

Sketch the graph y=-x^3, using this sketch y=-x^(1/3)

The first step in figuring out this question is to first determine what the y=x3 looks like.If you are not already fimilar with this function, you can use some basic principles to find out wha...

DO
Answered by Deloris O. Maths tutor
3730 Views

y = Sin(2x)Cos(x). Find dy/dx.

Assume base differentiation knowledge: Sin(x) = Cos(x), Cos(x) = -Sin(x)The question combines the chain and product rule. To begin, start by splitting the equation: Sin(2x)Cos(x) = Sin(2x) x Cos(x)The pro...

SC
Answered by Saskya C. Maths tutor
13883 Views

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