Search over 10,000 free study notes

(x^2+4x+10)/(x+3)(x+4)(x+1) = A/(x+3) + B/(x+4) + C/(x+1) [A(x+4)(x+1) + B(x+3)(x+1) + C(x+3)(x+4)]/(x+3)(x+4)(x+1) = (x^2+4x+10)/(x+3)(x+4)(x+1) [A(x+4)(x+1) + B(x+3)(x+1) + C(x+3)(x+4)] = (x^2+4x+10) A(...

Differentiate the equationdy/dx=6x+2x(dy/dx)+2y-4y(dy/dx)Set this equal to zero and solve for dy/dx which gives:dy/dx=(2y+6x)/(4y-2x)For x=2 and y=4 dy/dx=5/3(y-y_o)=m(x-x_o)y-4=(5/3)(...

3x³ /3 + 4x⁶/(6x3) = x³ + 2x⁶/9 + c

Firstly, ensure both numerator and denominator are factorised fully so that any possible cancellations can happen - making it easy for yourself is always a good idea. Now, turn it into partial fractions. ...

Firstly we notice that the numerator is the derivative of the denominator so we can use integration by subsitution method. Setting u=x^(2)+1. We can differentiate this to get du/dx=2x Subbing in dx=du/2x ...