Top answers

Maths
A Level

A circle with centre C has equation: x^2 + y^2 + 20x - 14 y + 49 = 0. Express the circle in the form (x-a)^2 +(y-b)^2=r^2. Show that the circle touches the y-axis and crosses the x-axis in two distinct points.

Firstly we rearrange the expression to the required form:x2 + y2 + 20x - 14y + 49 = 0 which gives (x + 10)2 - 100 + (y - 7)2 - 49 + 49 = 0 and so ...

JI
Answered by John I. Maths tutor
6799 Views

Integrate ln(x/7) with respect to x

Firstly split up the ln(x/7) = ln(x) - ln(7) using rules of logarithms learnt in your first year of A-levels, as this will reduce any likely error.Secondly, recognise that the -ln(7) term is constant, and...

AS
Answered by Arjun S. Maths tutor
2843 Views

A curve passes through the point (4, 8) and satisfies the differential equation dy/dx = 1/ (2x + rootx) , Use a step-by-step method with a step length of 0.3 to estimate the value of y at x = 4.6 . Give your answer to four decimal places.

h dy/dx (4) = 0.03y(4.3) = 8+0.03 = 8.03y(4.6) = y(4.3) + 0.3 dy/dx(4.3) = 8.0581 to 4 d.p

KW
Answered by Keni W. Maths tutor
3314 Views

Express 2(x-1)/(x^2-2x-3) - 1/(x-3) as a fraction in its simplest form.

The answer is 1/(x+1)I began by factorising the denominator of the first fraction:2(x-1)/(x^2-2x-3) - 1/(x-3) = 2(x-1)/(x-3)(x+1) - 1/(x-3) Next, I multiplied both the numerator and the denominator of the...

DR
Answered by Devan R. Maths tutor
8061 Views

What is the equation of the tangent to the curve y=x^3+3x^2+2 when x=2

dy/dx=3x^2+6xx=2m=3(2)^2+6(2)=24at x=2 y=22(2,22)y-22=24(x-2)y-22=24x-48y=24x-26

KH
Answered by Kieran H. Maths tutor
3571 Views

We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences