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Differentiating each term separately, and using implicit differentiation to differentiate the functions of y by differentiating with respect to y and multiplying by dy/dx, we can obtain 6ydy/dx + ln2<...
y = arctan(x)tan(y) = xsec2(y) = dx/dyfrom cos2A + sin2A = 1, we know that 1 + tan2A = sec2A (divide by cos2A), so we substitute in1 + tan...
This indefinite integral (has no defined limits) should be evaluated by integration by substitution This is because you cannot integrate sin2xWhen doing integration by substitu...
This can be done with integration by substitution. If we let u=tanx then du/dx=sec^2(X). If we substitute U into the integrand we get it being u(sec^2(X))dx. rearranging the du/dx equation to make dx the ...
To start with, we want to put this into quadratic form, where we have ax^2+bx+c=0. We notice that there are terms on both sides of the equation. So we can expand the right hand side and then bring all th...
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