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Maths
A Level

Differentiate x^3⋅cos(5⋅x) with respect to x.

In order to solve this problem we will have to use the product rule as follows: d/dx[x^3⋅cos(5⋅x)]=[d/dx(x^3)]⋅cos(5x)+(x^3)⋅[d/dx[cos(5x)]]=(3⋅x^2)⋅cos(5⋅x)+(x^3)⋅−5⋅sin(5⋅x)=3⋅x^2⋅cos(5⋅x)−5⋅x...

TL
Answered by Tianyu L. Maths tutor
5622 Views

Points P and Q are situated at coordinates (5,2) and (-7,8) respectively. Find a) The coordinates of the midpoint M of the line PQ [2 marks] b) The equation of the normal of the line PQ passing through the midpoint M [3 marks]

a) For finding the midpoint M, the point M must be equidistant from P and Q in both the x and y axes. Hence, we consider the x and y axis separately. The midpoint of the x coordinates is essentially a mea...

JU
Answered by Justin U. Maths tutor
3774 Views

The gradient of the curve at A is equal to the gradient of the curve at B. Given that point A has x coordinate 3, find the x coordinate of point B.

We are told f(x) = (2x-5)^2 (x+3).In part b) we are asked to show that f'(x) = 12x^2 -16x -35, so for part (c) we shall assume this definition for f'(x). We are told that the x coordinate for A is 3. Call...

TF
Answered by Thomas F. Maths tutor
5795 Views

Solve x(5(3^0.5)+4(12^0.5))=(48^0.5) to the simplest form. (4 Marks)

The aim of the question is to equate x= into an expression.Step 1. Look to see if you can simplify the equation. On the left hand side of the equation you can see that 3 is a factor of 12. And also a fact...

RC
Answered by Richard C. Maths tutor
3171 Views

If a ball is dropped from 6m above the ground, how long does it take to hit the floor and what is its speed at impact (assuming air resistance is negligible)?

Distance, s = 6m ; initial speed, u = 0 m/s ; final speed, v = v m/s ; acceleration, a = 9.8 m/s (g) ; time, t = t sTime:s = ut + 0.5at2 , 6 = 0 + (0.5 x 9.8)t2 , 6 = 4.9t2

RR
Answered by Rebecca R. Maths tutor
4154 Views

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