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Maths
A Level

The curve C has equation y=(2x-3)^5, the point P lies on C and has coordinates (w, – 32), find (a) the value of w and (b) the equation of the tangent to C at the point P in the form y=mx+c , where m and c are constants.

(a) The curve is defined by y=(2x-3)^5. To find x=w when y=-32, we must substitute these values into the equation C and re-arrange to find w. -32=(2w-3)^5. First we must remove the power of 5 by doing pow...

JP
Answered by Jordan P. Maths tutor
11259 Views

Find the volume of revolution when the curve defined by y=xe^(2x) is rotated 2*pi radians about the x-axis between x=0 and x=1

This is a standard question that may be found in a C4 mathematics paper. Students should use knowledge of the volume of revolution formula V = piint_{a}^{b} y2dx to find the expression V =...

HS
Answered by Hanish S. Maths tutor
3071 Views

find the coordinates of the turning points of the curve y = 2x^4-4x^3+3, and determine the nature of these points

To begin, we must first use the fact that turning points of a graph occur at points where the gradient is equal to zero, in other words, points where dy/dx =0. Differentiating the equation with and settin...

JN
Answered by Jenny N. Maths tutor
6334 Views

The equation kx^2 + 4x + (5 – k) = 0, where k is a constant, has 2 different real solutions for x. Show that k satisfies k^2-5k+4>0.

This questions is a proof type question, which means that you need to get to a specific formula. Usually, these questions give you clues in order to prove it. In this case it tells you that the equation h...

AG
Answered by Alin G. Maths tutor
15452 Views

The equation of a curve C is (x+3)(y-4)=x^2+y^2. Find dy/dx in terms of x and y

Expand to get xy+3y-4x-12=x^2+y^2Rearrange to xy+3y-4x-12-x^2-y^2
Then you have to differentiate implicitly:
use product rule on xy to get:u = x v =ydu = 1 dv = dy/dx
so xy differentiates t...

RR
Answered by Ravi R. Maths tutor
3935 Views

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