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Maths
A Level

A curve has parametric equations x = 1- cos(t), y = sin(t)sin(2t). Find dy/dx.

Here we have x(t) and y(t) which are both functions of t, but we want dy/dx, which doesn't involve t, we therefore need to use the chain rule. The chain rule tells us that: dy/dx = (dy/dt) x (dt/dx).y = s...

WM
Answered by William M. Maths tutor
5842 Views

A curve is defined by the equation y^2 - xy + 3x^2 - 5 = 0. Find dy/dx.

2y dy/dx - x dy/dx - y + 6x = 0dy/dx (2y-x)= y-6xdy/dx= (y-6x)/(2y-x)

WA
Answered by Witold A. Maths tutor
4716 Views

Given that y={(x^2+4)(x−3)}/2x, find dy/dx in its simplest form.

Looking at the problem to start we can see that this is an algebraic division problemThere are three common methods you will come across for finding dy/dx for algebraic problems: The Chain Rule, The Produ...

MT
Answered by Meeza T. Maths tutor
6646 Views

How do I deal with parametric equations? x = 4 cos ( t + pi/6), y = 2 sin t, Show that x + y = 2sqrt(3) cos t.

Note: I have a screenshot of the question that I should be able to add to the work space. Q5 C4 June 2014 Edexcel.x + y = 2sqrt(3) cos tStart with x = 4 cos ( t + pi/6) and the trig identity cos(A + B) = ...

KD
Answered by Karina D. Maths tutor
9707 Views

Prove that (1-cos2x)/sin(2x) = tan(x) where x ≠ nπ/2

Starting from the left hand side we can substitute the sin and cos sum and difference formulas. These are sin(A+B) = sinAcosB + cosAsinBand cos(A+B) = cosAcosB - sinAsinBBecause x = A = B when substituted...

JB
Answered by Jed B. Maths tutor
8576 Views

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