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Maths
A Level

Find the integral of ((2(7x^(2)-xe^(-2x))-5)/x) . Given that y=27 at x=1, solve the differential equation dy/dx=((2(7x^(2)-xe^(-2x))-5)/-3x).y^(2/3) in terms of y.

Part A)Expand numerator in the integral to get 14x^(2) - 2xe^(-2x)-5Now divide by denominator to get 14x - 2e^(-2x) - 5/xNow integrate to get 7x^(2) + e^(-2x) - 5ln(x)Part B)Get all components of y on the...

GR
Answered by George R. Maths tutor
3968 Views

Express 1/(1+2x)(1-x) in partial fractions

1/(1+2x)(1-x)=(A/(1+2x))+(B/(1-x))1=A(1-x)+B(1+2x) Now set the bracket of one of A or B equal to 0 to get an equation with 1 unknown.Set x=11=A(1-1)+B(1+2(1))1=A(0)+B(3)1=3BB=1/3Set x=-(1/2)1=A(1-(-1/2))+...

LC
Answered by Luke C. Maths tutor
3758 Views

How do you find a turning point of a function using differentiation?

To find the location of turning points on a function, find the first derivative of the function, and then set the result to 0. if you then solve this equation, you will find the locations of the turning p...

NS
Answered by Nathan S. Maths tutor
50675 Views

A particle A of mass 0.1kg is moving at a speed of 1.5m/s to the right. It collides with a particle B of mass 0.3kg moving at a speed of 1.1m/s to the right. Calculate change in momentum of particle A if particle B has a speed of 1.4m/s after collision.

Momentum is conserved during the collision.Momentum = mass x velocityMomentum before = momentum after(mv)P1 + (mv)Q1 = (mv)P2 + (mv)Q2(0.1 x 1.5) + (0.3 x 1.1) ...

JS
Answered by Juliet S. Maths tutor
3296 Views

What is the area under the graph of (x^2)*sin(x) between 0 and pi

To solve this integral you need to use integration by parts twice. You separate the two term in the integral into x^2 and sin(x). You then multiple x^2 by the integral of sin(x) (-cos(x)) and apply the up...

KP
Answered by Khalil P. Maths tutor
3777 Views

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