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Use the chain rule, u = 3x-2dy/dx = dy/du du/dxdy/du = d(u^1/2)/du = 1/2 u ^-1/2power down and minus 1du/dx = 3constants =0so, dy/dx = 3 1/2 (3x-2)^-1/2= 3/2 (3x-2)^-1/2

Use the formula cos(A+B)=cosAcosB-sinAsinB, Rcos(theta+alpha)=Rcos(alpha)cos(theta)-Rsin(alpha)sin(theta)5=Rcos(alpha)2=Rsin(alpha)tan(alpha)=2/5alpha= 0.381R=sqrt(5^2+2^2)=sqrt(29)So, 5cos(theta) – 2sin(...

'Find dy/dx' means it wants us to differentiate. The rules for this are multiply the coefficient (number before x) by the current power, then decrease the power by 1.In this example:5x³ would b...

Rearrange the expression to create a familiar function with a known differencial: arcos(x)=y x= cos(y) Differenciate x with respect to y: dx/dy= -sin(y) We know that dy/dx= 1/(dx/dy), so rearange to find ...

Differentiating with respect to x gives:3x^2 -y^2- x 2y(dy/dx) = 03x^2 -y^2 = x2y(dy/dx)dy/dx = (3x^2 - y^2)/2xy