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x2 -x -12 = 0. Here we have rearranged the equation so that we have 0 on one side of the equation, allowing us to now factorise. (x - ...
Step 1: Differentiate the equation Y = X^3 + X + 6 to find the gradient of the line at any point. To do this, multiply each term of X by the old power and -1 from that power. This makes dy/dx = 3X^2 + 1.S...
1/(x(a-x)) = B(1/x + 1/(a-x)) Note: the '≡' sign (defined equivalence) can be used in place of '=' but this is not necessary to achieve full marks.Step: multiply both sides by x(a-x)1 = (x(a-x))B(1/x + 1/...
The question is asking to differentiate which means find dy/dx. If we think about the differentiation rules we know about, we see that we should use the product rule as y is a product (multiplication) of ...
When asked to find dy/dx, this means to differentiate. Differentiation is also a method of calculating the gradient of a line. (dy/dx = gradient.) The rule of differentiation is as follows: Step ...
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