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dy/dx = 2x + 3, m = dy/dx = 7 Equation of tangent is a straight line hence we use y-y1 = m(x-x1), y-1 = 7(x - 2), y = 7x - 13
From a given equation y = mx + c. Finding dy/dx allows us to see the gradient of the curve. In order to do this we can follow the formula:When y = xSAAnswered by Sebastian A. • Maths tutor29098 Views
Factorise the equation (the equation is quadratic in sin(x) )2 sin2(x) - sin(x) - 1 = 0(2sin(x) + 1)(sin(x) - 1) = 0Work out the solutions to the quadratic equation2sin(x) +1 = 0 or ...
Up until now you may have been given functions like f(x)= 7x^3 +cos(x) and been told just to differentiate. What your teacher really meant was to differentiate with respect to x. The chain rule allows us ...
The easiest way to do this is to break the integral up into it's separate parts. We have:integral of 4sqrt(x)andintegral of -6/x^3Both of which have constants that can be taken out, i.e. 4 and 6, re...
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