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To find the turning points, first find the first derivative of the equation by differentiating. Differentiating can be done in this equation by multiplying the number in front of the x by the power then l...
-> m1u1 + m2u2 = m1v1 + m2v22.4 - 0.6 = 0.4v1 + 0.90.9 = 0.4 v1v1 = 2.25m/s (direction unchanged)-> I = mv - mu= (0.3 x 3) - (0.3 x -2)= 1.5 Ns
They key is to integrate by parts, set u = x, u' = 1, v' = sinx, v = -cosxSo, integral(xsinx) =uv - integral(u'v)+c = -xcosx - integral(-cosx) +c = -xcosx +sinx + cwhich is the answer
The first step will be to rearrange the eqn so that the loose number appears on the RHS and the x and y terms are grouped. After this step the eqn will appear as x2 + 2x + y2 - 6y = ...
To be shown using a whiteboard.Use first principles to differentiate.