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In order to find the gradient we need to differentiate d/Dx = 2x + 2using our point, the gradient is 4using y = mx+cy = 4x +cusing our pointsy= 4x - 1

pi/2 and -pi/2

First find a root of the function: f(x)=x^3+2x^2-5x-6 f(2)=(2)^3+2*(2)^2-5*(2)-6 =0. Therefore, (x-2)(x^2+Ax+3)=0 where A is an unkown constant. Compare x^2 coeffecients: A-2=2, A=4. So (x-2)(x^2+4x+3)=0....

SUVAT Part (A) Part (B) S=? S=?U=0 U= Calc From A (V)V=? V= 0T=30s t=45sPart A: V=U+atV=0+530V= 150S=ut+at²S=0+530*30S=4500mPart B: S=(U+V)t/2S=7545S=3375mTotal Distance = 337...

cos(2x)=cos²(x) - sin²(x)use sin²(x) = 1 - cos²(x)so cos(2x)=cos²(x) - (1 - cos²(x))cos(2x)=2cos²(x) - 1so a = 2 and b = -1