Integrate ⌠( xcos^2(x))dx

We must first use trigonometric identities to simplify cos2(x). We can use the formula cos(A+B) = cos(A)cos(B) - sin(A)sin(B) , where A=x and B=x, so that we get cos(2x) = cos2(x) - sin2(x) = 2cos2(x) - 1. Rearranging this we find that cos2(x) = 1/2 + (cos(2x))/2 This gives us (⌠(x+xcos(2x))dx)/2 = 1/2(⌠( x)dx + ⌠( xcos(2x))dx) = x2 /4 + ⌠( xcos(2x))dx) /2 We can then use the integration by parts formula, ⌠(udv)dx = uv - f(vdu)dx , where u=x and dv=cos(2x), so that we get x2 /4 + ⌠( xcos(2x))dx) /2 = x2 /4 + xsin(2x)/4 - ⌠(sin(2x))dx)/4 = x2 /4 + xsin(2x)/4 + cos(2x)/8 Hence,the final answer is x2 /4 + xsin(2x)/4 + cos(2x)/8 + c

DA

Related Maths A Level answers

All answers ▸

Line AB has equation 6x + y - 4 = 1. AB is perpendicular to the line y = mx + 1, find m.


Find the area enclosed by the curve y = cos(x) * e^x and the x-axis on the interval (-pi/2, pi/2)


Find the equation of the normal to the curve at the point (1, -1 ): 10yx^2 + 6x - 2y + 3 = x^3


The function f (x) is defined by f (x) = (1-x)/(1+x), x not equal to -1. Show that f(f (x)) = x. Hence write down f ^-1 (x).