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Physics
A Level

A supertanker of mass 4.0 × 10^8 kg, cruising at an initial speed of 4.5 m s^(–1), takes one hour to come to rest. Assume the force slowing down the tanker is constant.

From newton's first law, an object remains in its inertial frame until a force acts upon it. This means that according to a stationary observer, the object will remain at rest or continue moving at the...

JC
Answered by Jack C. Physics tutor
10370 Views

How do I resolve forces on a slope?

For any question which asks you to consider multiple forces acting on a body, the first thing you should do is draw a clear diagram, with all forces (and in this case angles) labelled.Once this has been d...

DB
Answered by Dan B. Physics tutor
11418 Views

How do I find how much radioactive material is left after time t if I know its half-life?

To answer this question, all you have to know is that the amount of material as a function of time, M(t), is related to the decay constant, λ, by the equation

M(t) = M0exp(-tλ)...

WS
Answered by Wilf S. Physics tutor
2840 Views

A motorist traveling at 10m/s, was able to bring his car to rest in a distance of 10m. If he had been traveling at 30m/s, in what distance could he bring his cart to rest using the same breaking force?

By just a quick look you might be tempted to say 30 m. However the key information is that the breaking force is the same. We can calculate the deceleration of the car when at 10m/s using the equation ...

CT
Answered by Charis T. Physics tutor
21011 Views

A car is moving along a straight horizontal road, with a constant acceleration. The car passes point A, with a speed of ums(-1). 10 seconds later, passes point B, with a speed of 45 ms(-1). The distance from A to B is 300m. Find u.

Here, we must consider our UVAST equations of motion, and our variables.

U=?ms^(-1),  V=45ms^(-1) , A=?ms^(-2),   S= 300m,   T=10s

Our equations of motion are:

AM
Answered by Alice M. Physics tutor
8862 Views

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