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Maths
GCSE

How do you use Substitution to solve simultaneous equations?

For the equations 3x + 2y = 4 (1) and 4x + 5y = 17 (2), isolate one of the unknowns in one equation to one side, like so: 3x = 4- 2y. Next multiply the equations so that this unknown is the same in both. ...

NS
Answered by Niusha S. Maths tutor
2894 Views

Work out 2^14 ÷ (2^9)^2 in its simplest form

214 ÷ (29)2I would start with the second part of this equation as that looks like it needs simplifying. When 'powers of' are in brackets to each other, they are multipled ...

SD
Answered by Sion D. Maths tutor
6748 Views

60 students were taking a Maths, Physics or Chemistry exam. 38 of the students were male. 11 of the 32 students who were taking the Maths exam were female. 8 males were taking the Physics exam. 12 students were taking the Chemistry exam. One of the fe

60-38 = 22 females 32+12=44 students taking the Chemistry and Maths exam. Therefore 60-44=16 students were doing the Physics exam, so 16-8= 8 females were taking the Physics exam. This means that 22-11-8 ...

HB
Answered by Harry B. Maths tutor
2855 Views

What is the relationship between the lengths of a right angle triangle

The lengths of a right angle triangle can be summarised as follows: the sum of the lengths of the two shorter sides squared (the sides which vertice connect forms the right angle) is equal to square of th...

SG
Answered by stephanie g. Maths tutor
3340 Views

3y^2 + 10y + 3

3y2 + 10y + 33y2 = 3 * 1(3y + n) * (y + r)n * r = 3 hence to try whole numbers first n = 1 or 3 meaning r = 3 or 1 respectivey * n + 3y * r = 10yif n =1 and r = 3 then equivalent is ...

JH
Answered by Jack h. Maths tutor
3127 Views

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