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Maths
GCSE

Without expanding any brackets, work out the solutions of 9(x+3)^2 = 4

To solve for x first divide both sides by 9, giving the equation:(x+3)2 = 4/9Then square root both sides, leading to:x+3 = +/- 2/3Finally subtract 3 from both sides leaving:x = -11/3 or x = -7/...

MT
Answered by Modestas T. Maths tutor
5015 Views

Solve the simultaneous equations: 3x + y =11; 2x + y = 8

subtract one from the other to eliminate y: 3x+y=11; 2x+y=8 --> x=3substitute value of x back in and solve for y: 3(3)+y=11; 9+y=11; --> y=2

IH
Answered by Israel H. Maths tutor
3113 Views

(a) Expand and simplify (x − 3)(x + 5), ..2 marks.. (b) Solve x^2 + 8x − 9 = 0 ..3 marks..

(a) Remember: Multiply each term in the left bracket by every term in the right bracket.(x-3)(x+5) = x2+ 5x - 3x -15.Collecting all of the like terms:= x2+ 2x -15.
(b) Solve x

JW
Answered by Jack W. Maths tutor
9626 Views

Simplify the following expression: √48+√(16 3/9) Give your answer in the form: (a√3)/b where a and b are integers.

The key to this question is to stay calm and not let yourself be intimidated. You can use the information provided in the question to give you a clear direction to head in- you want to factorise out root ...

RW
Answered by Rob W. Maths tutor
3418 Views

Differentiate the equation 3x^4+6x^2-7x+2

To differentiate, multiply the power by the coefficient and then take one off the power so the answer is 12x3 + 12x - 7

AS
Answered by Aimee S. Maths tutor
2745 Views

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